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AC=3AB
C-A=3(B-A)
C - (-1,2) = 3[(2,-5)-(-1,2)]
C - (-1,2) = 3[(2+1,-5-2) ]
C - (-1,2) = 3(3,-7)
C- (-1,2) = (9,-21)
C = (9,-21)+(-1,2)
C = (9+(-1); -21+2)
C = (8,-19)
Espero te sirva
Saludos Diego