2 NH3 + Cl2 + 2 NaOH → N2H4 + 2 NaCl + 2 H2O
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2 NH3 + Cl2 + 2 NaOH → N2H4 + 2 NaCl + 2 H2O
Mm NH3 = 17 g/molCl2 = 71 g/mol
gCl2 = 265 g NH3 x 1 mol NH3 x 1 mol Cl2 x 71 g Cl2
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17 g NH3 2 mol NH3 1 mol Cl2
g Cl2 = 553.38