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d = a (b/1+c)
ab = d(a+c)
ab = ad+cd
ab-ad = cd
a(b-d) = cd
a = cd/b-d
ab = d(a+c)
ab = ad+cd
ab-ad = cd
a(b-d) = cd
a = cd/b-d
Myślę,że pomogłam.