Doprowadz do najprostszej postaci wyrażenie (1- sin alfa)(1+sin alfa)-cos do potęgi drugiej alfa.
(1-sinα)(1+sinα)-cos²α=
1+sinα-sinα-sinα²-cos²α=
1-sin²α-cos²α=
1=sin²α+cos²α
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(1-sinα)(1+sinα)-cos²α=
1+sinα-sinα-sinα²-cos²α=
1-sin²α-cos²α=
1=sin²α+cos²α