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ax-3=y
y=ax-3 proste sa prostopadle,jezeli iloczyn ich wspol. kierunkowych = -1
a(a-4)= -1
a²-4a+1=0 ,Δ=b²-4ac ,Δ=12 , √Δ=√12=2√3
a1=(-b-√Δ)/2a
a1=(4-2√3)/2
a1=2-√3
a2=(-b+√Δ)2a
a2=(4+2√3)/2
a2=2+√3
proste sa prostopadle dla a=2-√3 ;a=2+√3