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6) Jest to ostrosłup prawidłowy czworokątny
P p=a ^2
P p=8^2=64 cm^2
a*h
P b=4* ----------- =2ah
2
Pb=2*8*7=112 cm^2
P c=P p+P b
P c=64+112=176 cm^2
Pole powierzchni całkowitej wynosi 176 cm^2