do 150 g roztworu 5-procentowego azotanu (V) potasu dolano 50 g wody. Oblicz stężenie procentowe otrzymanego roztworu.
mr=150g
cp1=5%
ms1=?
ms=cp*mr/100%
ms=5*150/100
ms=750/100
ms=7,5g
mr2=150+50=200
ms2=7,5g
cp=?
cp=ms/mr * 100%
cp=7,5/200 * 100
cp=750/200
cp=3,75%
mr1=150g
c%1=5%
ms1=x
c%1=ms1/mr1*100%
ms1=7,5 g
mr2=150+50=200 g
ms2=7,5 g
c%=x
c%2=ms2/mr2*100%
c%=7,5/200*100
c%=3,75%
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mr=150g
cp1=5%
ms1=?
ms=cp*mr/100%
ms=5*150/100
ms=750/100
ms=7,5g
mr2=150+50=200
ms2=7,5g
cp=?
cp=ms/mr * 100%
cp=7,5/200 * 100
cp=750/200
cp=3,75%
mr1=150g
c%1=5%
ms1=x
c%1=ms1/mr1*100%
ms1=7,5 g
mr2=150+50=200 g
ms2=7,5 g
c%=x
c%2=ms2/mr2*100%
c%=7,5/200*100
c%=3,75%