dlugosc prostakata wynosi 23,45m,a szerokosc stanowi 0.6 jego dlugosci.oblicz pole i obwod tego prostakata
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P=a*b
P=23,45*0,6= 14,07m
V=2a+2b
V=2*23,45+2*0,6=46,9+1,2=48,1
a=23,45m
b=0,6*23,45m=14,07m
ob=2a+2b
ob=2*23,45m+2*14,07m=46,9m+28,14m=75,04m
P=a*b
P=23,45m*14,07m=329,9415mKw