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a-b-ab+1=
-b-ab+1+a=
-b(1+a)+1(1+a)=
(1-b)(1+a)
czyli odp.b
lub tak
a.
(a+1)(b-1) =ab-a+b-1=-a+b+ab-1 ≠ a-b-ab+1
b.
(1-b)(1+a) =1+a-b-ab=a-b-ab+1
c.
(a-1)(b+1) =ab+a-b-1=a-b+ab-1 ≠ a-b-ab+1
d.
(a +b)(1+a)=a+a²+b+ab=a²+a+ab+b ≠ a-b-ab+1