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m-1≠0
m≠1
Δ>0
Δ=(m²+1)²-4(m-1)(m²+m)=m⁴+2m²+1-4(m³+m²-m²-m)=
=m⁴+2m²+1-4m³-4m = m⁴-4m³+2m²+4m+1>0
m⁴-4m³+2m²+4m+1>0
Nie można znaleźć dzielnika, sprawdź czy masz dobrze napisane zadanie