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(x-3)(x²+3x+9)≡mx³+n
x³ +3x² +9x -3x² -9x -27 ≡ mx³ +n
x³ - 27 ≡ mx³ + n..........dándole forma:
1x³ + (-27)=mx³ + n
Igualando términos:
m=1 ...y n=-27
PIDEN:
m+n=1+(-27)= -26