Dina mempunyai dua mainan kubus ajaib yang setiap sisi berlainan warna. perbandingan volume kedua kubus adalah V1 : V2 = 8 : 27. jika volume kubus kedua 135 cm3. Hitunglah luas permukaan kubus pertama
Takamori37
![V_1:V_2=8:27 \\ V_1:135=8:27 \\ V_1=\frac{135\times 8}{27} \\ V_1=5\times 8 \\ V_1=40 \\ s_1^3=40 \\ s_1=\sqrt[3]{40} \\ \\ Lp_1=6s^2 \\ Lp_1=6(\sqrt[3]{40})^2 \\ Lp_1=6\sqrt[3]{1600}$ cm^2$ \\ Lp_1\approx 70.1764$ cm^2$](https://tex.z-dn.net/?f=V_1%3AV_2%3D8%3A27+%5C%5C+V_1%3A135%3D8%3A27+%5C%5C+V_1%3D%5Cfrac%7B135%5Ctimes+8%7D%7B27%7D+%5C%5C+V_1%3D5%5Ctimes+8+%5C%5C+V_1%3D40+%5C%5C+s_1%5E3%3D40+%5C%5C+s_1%3D%5Csqrt%5B3%5D%7B40%7D+%5C%5C+%5C%5C+Lp_1%3D6s%5E2+%5C%5C+Lp_1%3D6%28%5Csqrt%5B3%5D%7B40%7D%29%5E2+%5C%5C+Lp_1%3D6%5Csqrt%5B3%5D%7B1600%7D%24+cm%5E2%24+%5C%5C+Lp_1%5Capprox+70.1764%24+cm%5E2%24 "V_1:V_2=8:27 \\ V_1:135=8:27 \\ V_1=\frac{135\times 8}{27} \\ V_1=5\times 8 \\ V_1=40 \\ s_1^3=40 \\ s_1=\sqrt[3]{40} \\ \\ Lp_1=6s^2 \\ Lp_1=6(\sqrt[3]{40})^2 \\ Lp_1=6\sqrt[3]{1600}$ cm^2$ \\ Lp_1\approx 70.1764$ cm^2$")
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