Question

[(x + √4x²) : 3 + √2] = [1 : (3- 2√2)] Tentyukan nilai x!

Answer 1

[(x + √4x²) : 3 + √2] = [1 : (3- 2√2)]
[(x+2x)/3 + (3√2)/3] = [1 : (3- 2√2)]
3x+3√2 = 3/(3-(2√2))
(3x+3√2)(3-(2√2)) = 3
9x-6x√2+9√2-12 = 3
9x-6x√2 = 3-(9√2)+12
x(9-6√2) = 15-9√2
x = (12-9√2 / 9-6√2) x (9+6√2 / 9+6√2)
x = (108 - 72√2 - 81√2 - 108) / (81 + 54√2 - 54√2 -72)
x = 153√2 / 9
x = 17√2

Answer 2

Jawab:
x+√4x^2/3 +√2=1/3-2√2
x+√4√x^2/3+√2=1/3-2√2
x+2√x^2/3+√2=1/3-2√2
x+2x/3+√2=1/3-2√2
5x/3+√2=1/3-2√2
5x/3=1/3-2√2-√2
5x/3=1/3-3√2
5x=(1/3-3√2) x 3
5x=3(1/3-3√2)
x=3(1/3-3√2)/5

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