Question

Diketahui x,y,z adalah 3 bilangan positif. Jika xy=15 , yz=12 xz=5 maka tentukan nilai xyz

Answer 1

xy.yz.xz = 15.12.5 = 900
x².y².z² = 900 -> (xyz)² = 900 -> xyz = √900 -> xyz = 30

Answer 2

xy=15 , yz=12 xz=5
(xy)(yz)(xz) = 15(12)(5)
(xyz)² = 900
xyz = √900
Jadi, nilai xyz = 30