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tan teta= 3 akar 3 /-3
tan teta=- akar 3
teta = 120 (kuadran 2 krn x = - , y = +)
r = akar (-3 ^2 + (3akar3)^2)
=akar ( 9 + 27)
= akar 36
=6
koordinat kutub :
=( r, teta)= (6, 120 derajat)