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Pembahasan :
f(x) = ax + b
f(2) = -2
a(2) + b = -2
2a + b = -2 ....... (1)
f(-3) = 13
a(-3) + b = 13
-3a + b = 13 ...... (2)
Eliminasi (1) dan (2)
2a + b = -2
-3a + b = 13
------------------ -
5a = -15
a = -15/5
a = -3
substitusikan a = -3 ke (1)
2a + b = -2
2(-3) + b = -2
-6 + b = -2
b = -2 + 6
b = 4
f(x) = ax + b
f(x) = -3x + 4
f(4) = -3(4) + 4
f(4) = -12 + 4
f(4) = -8
Jadi nilai dari f(4) adalah -8
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Untuk contoh soal lainnya, bisa dilihat di link berikut
brainly.co.id/tugas/786832
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Kelas : 8
Mapel : Matematika
Kategori : Fungsi
Kata Kunci : Menentukan rumus fungsi
Kode : 8.2.2