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(fog)(x) = 4x² - 6x + 10
f(3) = ...........?
Penyelesaian:
f⁻¹(x) = (x + 1)/2
(fog)(x) = f(g(x)
4x² - 6x + 10 = f(2x - 1)
f(x) = (fog)(f⁻¹(x))
= 4[(x + 1)/2]² - 6[(x + 1)/2] + 10
= 4[(x² + 2x + 1)/4] - 3(x + 1) + 10
= x² + 2x + 1 - 3x - 3 + 10
= x² - x + 8
f(x) = x² - x + 8
f(3) = 3² - 3 + 8
= 9 - 3 + 8
= 14
Jadi, nilai dari f(3) = 14