Question

Diketahui F¹(x)=3x²+4x-10.Jika (-2)= 5,maka F(x)=​

Answer 1

Verified answer

f'(x) = 3x^2 + 4x - 10

f(x) = integral f(x)

f(x) = 3/3 x^3 + 4/2 x^2 - 10x + c

f(x) = x^3 + 2x^2 - 10x + c

* mencari nilai c (konstanta)

f(-2) = 5

(-2)^3 + 2(-2)^2 - 10(-2) + c = 5

-8 + 8 + 20 + c = 5

20 + c = 5

c = 5 - 20

c = - 15

maka :

f(x) = x^3 + 2x^2 - 10x - 15

semoga membantu,maaf jika salah

Answer 2

Penyelesaian:

f'(x) = 3x^2 + 4x - 10

integral (3x^2 + 4x - 10) dx

= x^3 + 2x^2 - 10x + C

Jika f(-2) = 5

5 = x^3 + 2x^2 - 10x + C

5 = (-2)^3 + 2(-2)^2 - 10(-2) + C

5 = - 8 + 8 + 20 + C

5 = 20 + C

- 15 = C

Maka rumus

f(x) = x^3 + 2x^2 - 10x - 15

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Integral Tak Tentu Fungsi Aljabar

Kode: 11.2.10

Kata Kunci: Rumus f (x)