Question

Persamaan garis singgung kurva y=3x²+4x-5 dititik (1,2) adalah​

Answer 1

*)y=3x²+4x-5

*)y' = m = 6x+4

*) subtitusikan x

m = 6x+4 = 6(1)+4 = 10

*) pgs

y-y1 = m(x-x1)

y-2 = 10(x-1)

y-2 = 10x-10

y-10x+8 = 0