Jawab:
Turunan
gradien garis m = y'
Penjelasan dengan langkah-langkah:
i) cari titiksinggung
kurva y = 2x³
absis 1/2 --> x = 1/2 , y = 2( 1/2)³ = 2/8= 1/4
titik singgung (x1, y1) = ( 1/2 , 1/4)
ii) cari gradien garis singgung
m = y' = 6x²
x= 1/2 --> m = 6 (1/2)² = 6 (1/4)
m = 3/2
iii) pers, gasing y - y1 = m(x - x1)
y- 1/4= 3/2 ( x -1/2)
y - 1/4 = 3/2x - 3/4 ....kalikan 4
4y - 1 = 6x - 3
4y = 6x- 2
6x - 4y - 2= 0
3x - 2y - 1= 0
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Verified answer
Jawab:
Turunan
gradien garis m = y'
Penjelasan dengan langkah-langkah:
i) cari titiksinggung
kurva y = 2x³
absis 1/2 --> x = 1/2 , y = 2( 1/2)³ = 2/8= 1/4
titik singgung (x1, y1) = ( 1/2 , 1/4)
ii) cari gradien garis singgung
m = y' = 6x²
x= 1/2 --> m = 6 (1/2)² = 6 (1/4)
m = 3/2
iii) pers, gasing y - y1 = m(x - x1)
y- 1/4= 3/2 ( x -1/2)
y - 1/4 = 3/2x - 3/4 ....kalikan 4
4y - 1 = 6x - 3
4y = 6x- 2
6x - 4y - 2= 0
3x - 2y - 1= 0