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⇔ a - 2b = 2
5a = 3 + 3b
⇔ 5a - 3b = 3
Di eliminasi kn nilai x, maka tentukan nilai y, diperoleh
a - 2b = 2 |x5
5a - 3b = 3 |x1
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5a - 10b = 10
5a - 3b = 3
____________ -
(-7)b = 7
b =
b = (-1)
Di substitusi kn nilai b = (-1), maka tntukan nilai a, diperoleh
a - 2b = 2
a - 2(-1) = 2
a + 2 = 2
a = 2 - 2
a = 0
Mka nilai 4a + 3b adalah
4a + 3b = 4(0) + 3(-1) = 0 + (-3) = (-3) (a)
10b + 10 = 3 + 3b
7b = - 7
b = -1
a= 2(-1) + 2
a = 0
4(0)+3(-1) = -3