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Verified answer
4x+5y=120y=(120-4x)/5
x.y=x.(120-4x)/5
x.y=(120x-4x^2)/5
f(x)=x.y=(120x-4x^2)/5
Nilai maksimum adalah f'(x)=0
f'(x)=0
(120-8x)/5=0
120-8x=0
8x=120
x=15
4x+5y=120
4(15)+5y=120
5y=120-60
y=60/5=12
x.y=15.12=180