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Verified answer
Kubus ABCD.EFGHrusuk = 3 cm
Perhatikan ∆BGH
jarak G ke diagonal BH = tinggi ∆BGH dg alas BH = GP
BG × GH = BH × GP
3√2 × 3 = 3√3 × GP
GP = √6 cm
Jarak G ke diagonal BH = √6 cm ✔