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P = 3.1 atmV = 10 LitrosT = 27 ºC + 273 = 300 KR = 0.082 (L atm / mol K)n = ?
aplicar la ley de los gases ideales
V x P = n x R x T n = m/Mm sustituir
V x P = (m/Mm) X R x T
V x P x Mm = m x R x T
Mm O = 16 g/mol
m = ( 10 L x 3.1 atm x 16 g/mol ) / 0.082 (L atm / mol K) x 300 K
m = 20.16 g de oxigeno