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La distancia del foco al vértice secundario es a. El eje menor mide 2b
Por lo tanto (2 b)² = a² + a² = 2 a²: b² = a²/2
c = √(a² - b²) = √(a² - a²/2) = a/√2
Nos queda e = (a/√2) / a = 1/√2 = 0,707
Saludos Herminio