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39,132 g ----------------- x = 39,132*1/18 = 2,174 moles
peso molecular del CO2 = 44 g
44 g --------------------------- 1 mol
95,656 g ------------------- x = 95,656*1/44 = 2,174 moles
en 1 mol de H2O --------------- 2 g de H
en 2,174 moles ------------ x = 2,174*2/1 = 4,348 g de H
en 1 mol de CO2 ----------------- 12 g de C
en 2,174 moles ---------------- x = 2.174*12/1 = 26,088 g de C
g de O = 100 - 4,348 - 26,088 = 69,564 g de O
moles de O = 69,564/16 = 4,34775 moles
moles de H = 4,348/1 = 4,348 moles
moles de C = 26,088/12 = 2,174 moles
relaciones molares:
C/C = 2,174/2,174 = 1
H/C = 4,348/2,174 = 2
O/C = 4,34775/2,174 = 2
Fórmula empírica: CH2O2