Question

dengan caranya terimakasih

Answer 1

#F

(8) lim(x->0) ( 2 x tan 3x) / (1 - cos² x)

= lim(x->0) (2x tan 3x)/ (sin² x) = (2x)(3x) /(x²)= 6x²/x² = 6

(9) lim(x->0) ( 2 sin² 2x , sin x ) / (x². tan 3x)

= lim(x->0) (sin² 2x / x²) . lim(x->0) ( 2 sin x)/ (tan 3x)

= (2x)²/x² . (2x/3x)

= (4x²/x²) (2x/3x)

= 4(2/3)

= 8/3