Question

dengan caranya terimakasih

Answer 1

#F

10) lim(x->0) (5x²-2x) / ( sin 5x - tan 2x)

lim (x -0) = (5x²/x - 2x/x) / (sin 5x/x - tan 2x/x)

= (5x - 2) /(5x/x - 2x/x)

= (5x - 2)/(5 - 2)

= (0 - 2)/(5-2)

= - 2/3

11) lim(x->0) (x²-9) /( sin (x - 3)

lim(x->0) ( x -3)( x + 3) / sin (x -3)

lim,(x->0) (x-3)/ sin(x-3) . ( x + 3)

= lim(x->0) 1(x+3)

= 0 + 3

= 3