Question

Dari persamaan kuadrat jika
Nilai p adalah....

Answer 1

3x² + 4x - p = 0
x₁ : x₂ = 1 : 3

x₁+x₂ = -b/a = -4/3
x₁.x₂ = c/a = -p/3

x₁ : x₂ = 1 : 3
x₂ = 3x₁

substitusi
x₁+x₂ = -4/3
x₁+3x₁ = -4/3
4x₁ = -4/3
x₁ = - 1/3

substitusikan kembali
x₂ = 3x₁
x₂ = 3 (-1/3)
x₂ = -1

temukan p:
x₁.x₂ = -p/3
(- 1/3) (-1) = -p/3
1/3 = -p/3
p = -1

semoga membantu :)

Answer 2

3x² + 4x - p = 0   ----> a = 3  ; b = 4   ;  c = - p
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= 

untuk x =  ...
3 + 4. - p = 0
3. - - p = 0
- p = 0
- p = 0
- 1 - p = 0
     - p = 1
       p = - 1