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b) x3-2x+1-(-x3+3X)= x3-2x+1+x3-3x= 2x3-5x+1
c)x3-2x+1-(2x+3)= x3-2x+1-2x-3= x3-4x-2
d) (x3-2x+1)(-x3+3x)= -x6+3x4+2x4-6x2-x3+3x= -x6+5x4-x3-6x2+3x
e) (x3-2x+1)(2x+3)= 2x4+3x3-4x2-6x+2x+3= 2x4+3x3-4x2-4x+3
f) x3-2x+1-(2x+3)-x3+3x= x3-2x+1-2x-3-x3+3x= -x-2
g) (2x+3)(x3-2x+1)-3(-x3+3x)= 2x4-4x2+2x+3x3-6x+3+3x3-9x= 2x4-6x3-4x2-13x+3
mam nadzieje ze dobrze ;)