Dany jest wielomian W(x)=x^2+2x +5x+10. Wyznacz pierwiastki tego wielomianu i oblicz jaka wartosc przyjmuje dla x=-3
w(x)=x(x+2)+5(x+2)
w(x)= (x+5)(x+2)
pierwiastki: x+5=0 x+2=0
x=-5 x=-2
w(-3)= -3^2 + 2* (-3) + 5 (-3) +10
=9-6-15+10=-2
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w(x)=x(x+2)+5(x+2)
w(x)= (x+5)(x+2)
pierwiastki: x+5=0 x+2=0
x=-5 x=-2
w(-3)= -3^2 + 2* (-3) + 5 (-3) +10
=9-6-15+10=-2