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Dane :
c=16
a=9
b=?
Z Tw. Pitagorasa mamy :
a²+b²=c²
9²+b²=16²
b²=16²-9²
b²=256-81
b²=175
b=5√7
c=16
z tw. Pitagorasa a²+b²=c²
9²+b²=16²
81+b²=256
b²=175
b=√175
b=5√7
b=?
c=16
a²+b²=c²
9²+ b²=16²
81+b²=256
b²= 256-81
b²=175
b=√175
b= 5√7
ODP Druga przyprostokatna wyniosi 5√7