a) h = 5
r = 4
V = 1/3* π* r2 *h wzór na objętośc stożka
V = 1/3* π* 42 *5
V = 1/3* π*16 *5
V = 80/3*π
V = 26 2/3π
b) h = 4
r = 5
V = 1/3* π* 52 *4
V = 1/3* π* 25 *4
V = 100/3*π
V = 33 1/3π
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a) h = 5
r = 4
V = 1/3* π* r2 *h wzór na objętośc stożka
V = 1/3* π* 42 *5
V = 1/3* π*16 *5
V = 80/3*π
V = 26 2/3π
b) h = 4
r = 5
V = 1/3* π* 52 *4
V = 1/3* π* 25 *4
V = 100/3*π
V = 33 1/3π