Question

czy lim 3n+1 przez 2n do potegi 2-1 = 0 prosze tez od obliczenia

Answer 1

lim [ ( 3n + 1)/( 2 n^2 - 1 ) ] =

n --> +oo

= lim [ ( 3/n + 1/n^2)/( 2 - 1/n^2) ] = [ ( 0 + 0)/( 2 - 0)] = 0/2 = 0

n --> +oo

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bo

lim  3/n = o

n--> + oo

lim 1/n^2  = 0

n --> + oo

lim  2  = 2

n-->+oo

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