mK₄[Fe(CN)₆]=4*39u+56u+6*12u+6*14u=368u 368g K₄[Fe(CN)₆]-------6*6,02*10^23 at. węgla 10g K₄[Fe(CN)₆]----------x at. węglax=0,98*10^23 at. węgla
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mK₄[Fe(CN)₆]=4*39u+56u+6*12u+6*14u=368u
368g K₄[Fe(CN)₆]-------6*6,02*10^23 at. węgla
10g K₄[Fe(CN)₆]----------x at. węgla
x=0,98*10^23 at. węgla