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Vo= 5 m³
Δt= 115-15= 100°C
Y= 3α
= 3×0,00007
= 0,00021 /°C
Dit:
Vt=..?
Penye:
Vt= Vo.(1+Y×Δt)
Vt= 5×(1+0,00021×100)
Vt= 5×(1+0,021)
Vt= 5×1,021
Vt= 5,105 m³
Δt = 115 - 15 = 100°C
α = 0,00007
Ditnya = Vt..?
Jawab =
= 5 (1 + 3 x 0,00007 x 100)
= 5 (1 + 0,00021 × 100)
= 5 (1 + 0,021)
= 5 × 1,021
= 5,105 m³