Limit
L'hos
lim (x→π/2) (1 - sin x)/cos x
= lim (x→π/2) - cos x/ - sin x
= cos π/2 / sin π/2
= 0/1
= 0 ✔
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
Limit
L'hos
lim (x→π/2) (1 - sin x)/cos x
= lim (x→π/2) - cos x/ - sin x
= cos π/2 / sin π/2
= 0/1
= 0 ✔