cos3x-cos2x=1
z tym,ze ta "3" to jest potega a ta "2" to nie jest potega :)
cos³x-cos2x=1
cos2x=cos²x-sin²x=cos²x-(1-cos²x)
cos2x=2cos²x-1
cos³x-2cos²x+1=1
cos²x(cosx-1)=0
cosx=0 ∨ cosx=1
x=π/2+2kπ ∨ x=2kπ
Pozdrawiam
Hans
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cos³x-cos2x=1
cos2x=cos²x-sin²x=cos²x-(1-cos²x)
cos2x=2cos²x-1
cos³x-2cos²x+1=1
cos²x(cosx-1)=0
cosx=0 ∨ cosx=1
x=π/2+2kπ ∨ x=2kπ
Pozdrawiam
Hans