cos= wyznacz wartość pozostałych funkcji trygonometrycznych tego kąta.
B- beta :)
cosβ = 2/3
sin²β + cos²β = 1
sin²β + (2/3)² = 1
sin²β = 1-4/9
sin²β = 5/9
sinβ = √5/3 lub sinβ = -√5/3
tgβ = sinβ/cosβ
tgβ = 2/3 / √5/3 = 2√5/5 lub tgβ = 2/3 /-√5/3 = -2√5/5
ctgβ = 1/tgβ
ctgβ = 1/2√5/5 = 0,5√5 lub ctgβ = 1/-2√5/5 = -0,5√5
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
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cosβ = 2/3
sin²β + cos²β = 1
sin²β + (2/3)² = 1
sin²β = 1-4/9
sin²β = 5/9
sinβ = √5/3 lub sinβ = -√5/3
tgβ = sinβ/cosβ
tgβ = 2/3 / √5/3 = 2√5/5 lub tgβ = 2/3 /-√5/3 = -2√5/5
ctgβ = 1/tgβ
ctgβ = 1/2√5/5 = 0,5√5 lub ctgβ = 1/-2√5/5 = -0,5√5
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)