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(a³-b³)=(a-b)(a²+ab+b²)
quedaría:
(64x³-y⁶)=(4x-y²)(16x²+4xy²+y⁴)
(4x-y²)((4x)²+(4x)(y²) +(y²)²
(4x-y)(16x ²+4xy +y∧4)