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ms = 20g
mbenzyny = Vr*dr
mb = 100*0,789 = 78,9g
mr = 20+78,9 = 98,9g
Cp = 20/98,9*100% = 2000/98,9 ≈ 20,2%
masa benzyny = 100cm³*0,789g/cm³ = 78,9 [g]
masa roztworu = 78,9g + 20g = 98,9g.
stężenie % = 20/98,9 *100 ≈ 20,22%.
Odp. Stężenie procentowe tego roztworu to (ok.) 20,22%.