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mw=500g
mr=120g+500g=620g
mr=620g
d=1,1g/cm3
v=m/dv=620/1,1
v=563,6cm3
mZnSO4=120g
MZnSO4=161g/mol
n=m/Mn=120/161
n = 0,75mola
Z def. stęż. molowego
0,75mola ZnSO4 ------ 563,6cm3 roztworu
xmoli ZnSO4 ---------- 1000cm3 roztworu
x=1,32mola ZnSO4
x = 1,32mol/dm3