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M H₂SO₄ = 98 g/mol
Cp = ms / m r-ru ×100 %
ms = (Cp × m r-ru) / 100%
Cm = n/V
n = ms/M
d = m/v --> v = m/d
Cm = (ms d) / (M m r-ru)
Cm = (Cp × m r-ru × d) / (M × m r-ru × 100%)
Cm = (Cp × d) / (M × 100%)
Cm = (96 × 1840) / (98 × 100) [ (% × g × mol)/(dm³ × g × %) = mol/dm³)] = 18.02 mol/dm³
Odp. Stezenie molowe tego kwasu wynosi 18.02 mol/dm³
d=1,84g/cm3=1840g/dm3
M H2SO4=98g/mol
Cm=?
Cm=Cp*d/M*100%
Cm=96%*1840g/dm3/98g/mol*100%
Cm=18,02mol/dm3