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x² - 10 x = - 21
x² - 10x + (10/2)² = -21 + (10/2)²
x² - 10 x + 25 = -21 + 25
x² - 10x + 25 = 4
(x - 5)² = 4 -----> kedua rua di akarkan, bair kuadratnya ilang
√(x - 5)² = √4
x - 5 = 2
x = 2 + 5
x = 7