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d1^ = (0-2)^2 + (2-0)^2
d1 = raiz de 8
d2^2 = (2+6)^2 + (0+6)^2
d2 =10
d3^2 = (0+6)^2 + (2+6)^2
d3 = 10
el perimetro es 10+10+raiz de 8 = 20 raiz de 8
El triángulo hallado es isosceles.