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Maka,
-1 ≤ x²-2 ≤ 1
Pisahkan,
Masalah 1.
-1 ≤ x²-2
x²-1 ≥ 0
(x+1)(x-1) ≥ 0
Maka, selesaian masalah 1
x ≤ -1 atau x ≥ 1
Masalah 2.
x²-2 ≤ 1
x²-3 ≤ 0
(x+√3)(x-√3) ≤ 0
Didapat selesaian:
-√3 ≤ x ≤ √3
Ambil irisan kedua masalah,
HP = {-√3 ≤ x ≤ -1 atau 1 ≤ x ≤ √3, x E R}