1. jika tan x = -√3 dan x tumpul, maka cos x = ..... 2. jika sin x = p, maka cos (180-x) =.... bantuin sama caranya ya kak
ImmanuelSinaga
1. tan di kuadran 2 tan (180 - x) = -tan x tan bernilai akar 3 jika sudut = 60' tan(180 - 60) = -tan 60 = -√3 ---=> x = 120 cos x = cos 120 = cos(90 + 30) = - sin 30 = - 1/2 2. cos (180 - x) = - cos x cos²x + sin²x = 1 cos²x + p² = 1 cos x = √(1 - p²) -cos x = - √(1-p²)
tan (180 - x) = -tan x
tan bernilai akar 3 jika sudut = 60'
tan(180 - 60) = -tan 60 = -√3 ---=> x = 120
cos x = cos 120 = cos(90 + 30) = - sin 30 = - 1/2
2. cos (180 - x) = - cos x
cos²x + sin²x = 1
cos²x + p² = 1
cos x = √(1 - p²)
-cos x = - √(1-p²)