Question

Bardzo proszę o pomoc jest to zadanie na jutro!!

f(x)=x²+5x-6
f(x)=-x²+4x-4
f(x)=x²+5x
f(x)=-x²+16

Answer 1

F(x)=x²+5x-6
a=1, b=5, c= -6
Δ=b²-4ac=(5)²-4*1*(-6)=25+24=49
√Δ=√49=7

x1=-b+√Δ /2a=
= -5+7/2*1=
=2/2=
=1

x2= -b-√Δ /2a=
=-5-7/2*1=
= -12/2=
= -6
x1=1, x2=-6




f(x)=-x²+4x-4
a=1, b=4, c=-4
Δ=16-4*(-4)=16+16=32
√Δ=√4*8=2√4*2=4√2

x1=-4+4√2/2= -4(1-√2)/2= -2(1-√2)
x2=-4-4√2/2= -4(1+√2)/2= -2(1+√2)



f(x)=x²+5x
a=1, b=5, c=0
Δ=25-4*1*0=25-0=25
√Δ=√25=5

x1=-5+5/2=0/2=0
x2=-5-5/2= -10/2= -5



f(x)=-x²+16
a= -1, b=0, c=16
Δ=0²-4*(-1)*16=0+64=64
√Δ=√64=8

x1=0+8/-2=8/-2= -4
x2=0-8/-2= -8/-2= 4

x1i x2 to pierwiastki równania
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