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(x+2)(x+1) = 0
x = -2 atau x = -1
1) untuk x₁ = - 2 dan x₂ = -1
PK baru akarna p= x₁+3 = -2 + 3 = - 1
dan q = x₂ + 2 = -1 + 2 = 1
x² - (p+q) x + p. q= 0
x² - ( -1-1) x + (-1)(1) = 0
x² + 2x - 1= 0
2) misal x₁ = -1 dan x₂ = -2
p= x₁+3 = -1 + 3 = 2
q = x₂ + 2 = -2 + 2 = 0
pK x² - (p+q) x + (pq) = 0
x² - 2x = 0