Question

Bantuin butuh banget jalannya sekarang

Answer 1

X^2+6x-5 = 0

a = 1
B = 6
c = -5
*mempermudah pembacaan..
x1 = p
x2 = q
-------

• p+q = -b/a = -6/1 = -6
• p.q = c/a = -5/1 = -5

(p+2) = m
(q+2) = n

• m+n = p+q+4 = (-6)+4 = -2
• m.n =
(p+2)(q+2)
= (p.q)+2p+2q+4
= (p.q)+2(p+q)+4
= (-5)+2(-6)+4 = -17+4 = -13

persamaan baru =

x^2-(m+n)x + (m.n) = 0
• x^2 -(-2)x + (-13) = 0
• x^2 +4x -13 = 0

Answer 2

Persamaan kuadrat x² + 6x - 5 = 0
pk baru akarnya x₁ +2 dan x₂ + 2
misal akar baru α = x1+2 --> x= α - 2 substitusikan ke
x² + 6x - 5= 0  --> (α-2)² + 6(α-2) - 5= 0
α² - 4α + 4 + 6α -12 - 5= 0
α² + 2a - 13 = 0